Hardy-Weinberg: Selection & Mutation::
Adding Selection to Hardy-Weinberg Analysis: Calculation of Genotype Frequencies. selection violates conclusions 1 and/or 2. heterozygote superiority [Fig.
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Hi guys,
I'm a bit stumbled on how to do these HW calculations, the ones I knew to do were pretty simple but these are pretty hard, any help on how to get me started?
Thanks!
Phenylketonuria is an inborn error of metabolism caused by autosomal recessive
gene. The frequency of this allele in the population is 0.03. Assuming Hardy-
Weinberg equilibrium, what is the expected incidence of phenylketonuria among the
Hardy-Weinberg::
Aug 21, 2000 The Hardy-Weinberg formulas allow scientists to determine whether Obviously, the Hardy-Weinberg equilibrium cannot exist in real life.
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offspring of all matings in which both parents are found to be carriers?
A. 0.0009
B. 0.03
C. 0.25
D. 0.5
E. 0.0145
This is one of those questions that throws a little extra information at you, which you have to ignore. The pertinent parts are: "autosomal recessive gene" and "expected incidence of PKU among the offspring of all matings in which both parents are...carriers" So, neither the Hardy-Weinberg equations, nor the frequency of the allele in the population matters because you've already established that both parents are carriers (heterozygotes), and you know from basic genetics that the offspring of heterozygotes will be in the ratios: 1/4 homozgyous dominant, 1/2 heterozygotes, and 1/4 homozygous recessive (having PKU). So, if both parents are carriers, then the incidence of PKU in their offspring is 1/4, so the answer is C, 0.25
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Hardy Weinberg Calculations?