so, a bomb with mass 1.2 kg moves in the pos. x-axis direction with a vel. of .5 m/s. when it reaches the origin, the bomb explodes into two pieces.
one piece travels at an angle of 31 degrees in respect to the pos. x-axis. that piece has a mass of .8 kg and had a velocity of .75 m/s in the x-direction and .45 m/s in the y-direction.
the other piece travels in the negative y-axis with a vel. of .9 m/s and has a mass of .4 kg.
what is the energy release by the explosion?
its multiple choice: the answers are (approximately):
a) .20 J
b) .24 J
c) .28 J
d) .32 J
e) .36 J
Hey Huey Lewis and the news were my favorite band:
dude, momentum is CONSERVED. find the "incoming" momentum subtract the "outgoing" momentum....that's the energy of the explosion...
It's hip 2 B square!
The energy released by the explosion is the change in enregy between the two "outgoing" pieces, and that of the "incoming" one piece.
....total energy(of motion) after explosion minus total energy(of motion) BEFORE explosion= explosive energy imparted to the objects.
Where was the last debate on wednesday with Mccain and Obama?
INSTANCE / WAITING FOR SPRING
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